(2x^2+10x-5)/(2x-2)

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Solution for (2x^2+10x-5)/(2x-2) equation: 


D( x )

2*x-2 = 0

2*x-2 = 0

2*x-2 = 0

2*x-2 = 0 // + 2

2*x = 2 // : 2

x = 2/2

x = 1

x in (-oo:1) U (1:+oo)

(2*x^2+10*x-5)/(2*x-2) = 0

2*x^2+10*x-5 = 0

2*x^2+10*x-5 = 0

DELTA = 10^2-(-5*2*4)

DELTA = 140

DELTA > 0

x = (140^(1/2)-10)/(2*2) or x = (-140^(1/2)-10)/(2*2)

x = (2*35^(1/2)-10)/4 or x = (-2*35^(1/2)-10)/4

(x-((-2*35^(1/2)-10)/4))*(x-((2*35^(1/2)-10)/4)) = 0

((x-((-2*35^(1/2)-10)/4))*(x-((2*35^(1/2)-10)/4)))/(2*x-2) = 0

( x-((-2*35^(1/2)-10)/4) )

x-((-2*35^(1/2)-10)/4) = 0 // + (-2*35^(1/2)-10)/4

x = (-2*35^(1/2)-10)/4

( x-((2*35^(1/2)-10)/4) )

x-((2*35^(1/2)-10)/4) = 0 // + (2*35^(1/2)-10)/4

x = (2*35^(1/2)-10)/4

x in { (-2*35^(1/2)-10)/4, (2*35^(1/2)-10)/4 }

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